What amount of heat is required to melt 1.5 kg of zinc, the initial temperature of which is 20 degrees?

m = 1.5 kg.

t1 = 20 ° C.

t2 = 420 ° C.

С = 380 J / kg * ° C.

q = 1.2 * 105 J / kg.

Q -?

Q = C * m * (t2 – t1) + q * m = (C * (t2 – t1) + q) * m.

Q = (380 J / kg * ° C * (420 ° C – 20 ° C) + 1.2 * 105 J / kg) * 1.5 kg = 408000 J.

Answer: to melt zinc, you need Q = 408000 J of thermal energy.



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