What amount of heat is required to melt 200 g lead with a temperature of 327 ° C?

What amount of heat is required to melt 200 g lead with a temperature of 327 ° C? (Specific heat of fusion of lead 2.5 10 to the 4th power J / kg, melting point of lead 327 ° C)

Initial data: m (mass of lead for melting) = 200 g; t (lead temperature) = 327 ºС.

Constants: according to the condition λ (specific heat of fusion of lead) = 2.5 * 10 ^ 4 J / kg; tmelt (melting point of lead) = 327 ºС.

SI system: m = 200 g = 0.2 kg.

Since lead is at its melting temperature, the heat consumption is only spent on the transition of lead to a liquid state:

Q = λ * m = 2.5 * 10 ^ 4 * 0.2 = 5000 J = 5 kJ.

Answer: It takes 5 kJ of heat to melt lead.