What amount of heat is required to vaporize 0.1 kg of ether with a temperature of 5 degrees Celsius?
| December 2, 2020 | education
Given:
m = 0.1 kg
t ° 1 = 5
c = 2350 J / kg * ° С
L = 350000 J / kg
Find: Q =?
Decision:
Q = Qheating + Qvaporization
Qн = cm (t ° 2-t ° 1)
Temperature t ° 2 is the boiling point of ether
t2 = 35 ° С
Qн = 2350 * 0.1 (35-5) = 7050 J
Qп = Lm
Qp = 350000 * 0.1 = 35000 J
Q = 7050 + 35000 = 42050 J
Answer: Q = 42050 J.
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