What amount of heat is seen in a conductor with a resistance of 1Ω for 30 seconds at a current of 4A?
| June 20, 2021 | education
Given: R (resistance of a given conductor) = 1 Ohm; t (duration of conductor operation) = 30 s; I (current) = 4 A.
The heat released in a given conductor is calculated using the Joule-Lenz law: Q = I ^ 2 * R * t.
Let’s calculate: Q = 4 ^ 2 * 1 * 30 = 480 J.
Answer: 480 J of heat will be released in a given conductor.
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