What amount of heat must be given to water with a mass of 10 g taken at a temperature of 0 degrees
| February 7, 2021 | education
What amount of heat must be given to water with a mass of 10 g taken at a temperature of 0 degrees in order to heat it up to the boiling point and evaporate.
m = 10 g = 0.01 kg.
C = 4200 J / kg * ° C.
q = 2.3 * 10 ^ 6 J / kg.
t1 = 0 ° C.
t2 = 100 ° C.
Q -?
The required amount of heat Q will be the sum of the amount of heat Q1 that goes to heat water from the temperature t1 = 0 ° C to the boiling point t2 = 100 ° C and the amount of heat Q2 that goes to evaporation at the boiling point: Q = Q1 + Q2.
Q1 = C * m * (t2 – t1).
Q1 = 4200 J / kg * ° C * 0.01 kg * (100 ° C – 0 ° C) = 4200 J.
Q2 = q * m.
Q2 = 2.3 * 10 ^ 6 J / kg * 0.01 kg = 23000 J.
Q = 4200 J + 23000 J = 27200 J.
Answer: for the evaporation of water, it is necessary to spend Q = 27200 J.
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