What amount of heat must be imparted to ice with a mass of m = 1.5 kg, located at a temperature

What amount of heat must be imparted to ice with a mass of m = 1.5 kg, located at a temperature of t = minus 20, in order to heat it to the melting point and completely melt it? (specific heat capacity of ice c = 2100 J / kg * Celsius, melting point of ice = 0 Celsius, specific heat of melting of ice lambda = 33300 J / kg

Given:

m = 1.5 kilograms is the mass of ice;

T1 = -20 degrees Celsius – ice temperature;

T2 = 0 degrees Celsius – the temperature at which ice melts;

c = 2100 J / (kg * C) – specific heat capacity of ice;

q = 33300 J / kg is the specific heat of melting of ice.

It is required to determine the amount of heat Q (Joule) required to heat the ice and melt it.

The amount of heat required to heat ice from temperature T1 to T2:

Q1 = c * m * (T2 – T1) = 2100 * 1.5 * (0 + 20) = 3150 * 20 = 63000 Joules;

The amount of heat to melt the heated ice:

Q2 = q * m = 33300 * 1.5 = 49950 Joules.

Total heat:

Q = Q1 + Q2 = 63000 + 49950 = 112950 Joules.

Answer: ice must be supplied with an amount of heat equal to 112950 Joules.