What amount of heat must be imparted to water weighing 1 kilogram in order to heat from 10 to 60

What amount of heat must be imparted to water weighing 1 kilogram in order to heat from 10 to 60 degrees the specific heat of water is 4,200 joules per kilogram.

Task data: m (water mass) = 1 kg; t0 (temperature before heating) = 10 ºС; t (final temperature) = 60 ºС.

Reference values: according to the condition Sv (specific heat capacity of water) = 4200 J / (kg * ºС).

The amount of heat that will need to be reported to 1 kg of water is determined by the formula: Q = Cw * m * (t – t0).

Calculation: Q = 4200 * 1 * (60 – 10) = 210 * 10 ^ 3 J = 210 kJ.

Answer: 1 kg of water must be given 210 kJ of heat.