What amount of heat must be imparted to water weighing 17 g, taken at a temperature of 8 C (degrees),

What amount of heat must be imparted to water weighing 17 g, taken at a temperature of 8 C (degrees), in order to heat it to the boiling point and evaporate it?

Given:
m = 17 g = 0.017 kg
s = 4200 J / kg * ° С
t1 = 8 ° C
t2 = 100 ° C
L = 2260000 J / kg
Find Q =?
Decision:
First you need to find the amount of heat that will be released when you bring water to a boil
Q1 = cm (t2-t1)
Q1 = 4200 J / kg * ° С * 0.017 kg * (100 ° -8 ° С) = 6568.8 J
Then we will find the amount of heat that will be released during vaporization
Q2 = Lm
Q2 = 2260000 J / kg * 0.017 kg = 38420 J
Find the total amount of heat
Q = Q1 + Q2
Q = 6568.8 J + 38420 J = 44988.8 J ≈ 45 kJ
Answer: Q = 45 kJ