What amount of heat must be spent in order to obtain steam at 100C from 5 kg ice taken at a temperature of -10C?

1) Q1 = 5 * 2100 * (0 – (- 10) = 5 * 21000 = 105000J
2) Q2 = 3.4 * 10 ^ 5 * 5 = 1700000J
3) Q3 = 5 * 4200 * (100-0) = 2100000J
4) Q4 = 5 * 2.3 * 10 ^ 6 = 11500000J
Q = Q1 + Q2 + Q3 + Q4 = 105000 + 1700000 + 2100000 + 11500000 = 15405000J
Answer: 15405000J or 15.405MJ



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