What amount of heat Q will be released when water with a mass of 120 kg is cooled by 25 ° C?

univerkov | August 6, 2021 | education

Initial data: Δt (change in water temperature during cooling) = 25 ºС; m (mass of water for cooling) = 120 kg.

Reference data: C (specific heat capacity of water) = 4200 J / (kg * K).

The amount of heat released during water cooling by 25 ºС is calculated by the formula: Q = C * m * Δt.

Let’s perform the calculation:

Q = 4200 * 120 * 25 = 12600000 J = 12.6 * 10 ^ 6 J = 12.6 MJ.

Answer: When water is cooled, 12.6 MJ of heat will be released.

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