What amount of heat was obtained by water weighing 200 g when heated from 10 to 30 celsius.
| December 16, 2020 | education
To find the amount of heat (Q), you need:
Q = c * m * (t2-t1)
Where: c-specific heat
m-mass of this substance (kg)
t2-end temperature
t1-initial temperature
Specific heat capacity of water is 4200
200 grams in kilograms 0.2
Now, all that remains is to substitute the values
Q = 4200 * 0.2 * (30-10) = 16 800 (J)
Answer: Q = 16 800 (J)
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