What amount of heat was released during the cooling of water, the volume of which is 10 liters

What amount of heat was released during the cooling of water, the volume of which is 10 liters, if the temperature changed from 100 to 40 C?

Data: V (volume of cooled water) = 10 l = 10 dm3 = 0.01 m3; t0 (initial temperature) = 100 ºС; t (temperature after cooling) = 40 ºС.

Constants: ρw (water density) = 1000 kg / m3; C (specific heat of water) = 4200 J / (kg * K).

The amount of heat released during cooling of water is determined by the formula: Q = C * m * (t0 – t) = C * ρw * V * (t0 – t).

Let’s calculate: Q = 4200 * 1000 * 0.01 * (100 – 40) = 2 520 000 J or 2.52 MJ.

Answer: When 10 liters of water cooled down, 2.52 MJ of heat was released.