What amount of heat was released when 10 g of steel was cooled by 8 * C? Specific heat of steel 500 J / (Kg * K)
| November 23, 2020 | education
Formula Q = cm Δt, where Q is the amount of heat that will be released, c is the specific heat capacity of steel, m is the mass of steel, Δt is the temperature
Q = 500J / kg * k * 0.01 kg * 8 = 40 J
You can also use the temperature in Kelvin and Celsius tk Δt – the same
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