What amount of heat will a 40 Ohm wire spiral release in 10 minutes if the current in it is 1A?

Initial data: t (time of current movement along a spiral) = 10 min; R (wire spiral resistance) = 40 ohms; I (current in the wire spiral) = 1 A.

SI system: t = 10 min = 10 * 60 = 600 s.

The amount of heat that the wire spiral will release in 10 minutes is determined by the formula: Q = I ^ 2 * R * t.

Let’s make a calculation: Q = 1 ^ 2 * 40 * 600 = 24,000 J or 24 kJ.

Answer: A wire spiral will release 24 kJ of heat in 10 minutes.