What amount of heat will a conductor with a resistance of 25 Ohm release in 15 minutes at a current of 2 A?

We calculate the amount of heat that the conductor will release in 15 minutes by applying the Joule-Lenz law:

Q = I² * R * t, where I is the value of the current strength (I = 2 A), R is the resistance of the conductor (R = 25 Ohm), t is the time the electric current passes through the conductor (t = 15 min = 15 * 60 s = 900 s).

Let’s calculate the amount of heat:

Q = I² * R * t = 2 ² * 25 * 900 = 90,000 J = 90 kJ.

Answer: The conductor will release 90 kJ of heat in 15 minutes.