What amount of heat will a conductor with a resistance of 50 Ohm release in 10 seconds at a voltage of 50 V?
| January 27, 2021 | education
Given: t (duration of the taken conductor) = 10 s; R (conductor resistance) = 50 ohms; U (mains voltage) = 50 V.
The heat released in the taken conductor can be determined using the Joule-Lenz law: Q = U ^ 2 / R * t.
Let’s make a calculation: Q = 50 ^ 2/50 * 10 = 500 J.
Answer: The taken conductor will release 500 J of heat in 10 s.
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