What amount of heat will be absorbed by 5 kg of ice at a temperature of 0 ° C and the specific heat of fusion is 340 kJ kg?

Ice will absorb the amount of heat that is necessary for the complete transformation of ice into water (ice will go from solid to liquid).

Q = λ * m, where λ is the specific heat of melting of ice (according to the condition of the problem λ = 340 kJ / kg = 340 * 10 ^ 3 J), m is the mass of ice (m = 5 kg).

Q = λ * m = 340 * 10 ^ 3 * 5 = 1,700,000 J = 1.7 MJ.

Answer: Ice will absorb 1.7 MJ of heat.

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