Ice will absorb the amount of heat that is necessary for the complete transformation of ice into water (ice will go from solid to liquid).
Q = λ * m, where λ is the specific heat of melting of ice (according to the condition of the problem λ = 340 kJ / kg = 340 * 10 ^ 3 J), m is the mass of ice (m = 5 kg).
Q = λ * m = 340 * 10 ^ 3 * 5 = 1,700,000 J = 1.7 MJ.
Answer: Ice will absorb 1.7 MJ of heat.
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