What amount of heat will be released by a lead plate weighing 1 kg, cooling by 7 C.

To calculate the heat released during cooling of the lead tile, we use the formula: Q = C * m * Δt, where C (specific heat capacity of lead, const) = 140 J / (kg * K); m (tile weight) = 1 kg; Δt (change in temperature of the lead plate during cooling) = 7 ºС.

Let’s perform the calculation: Q = C * m * Δt = 140 * 1 * 7 = 980 J.

Answer:   the lead tile will release 980 J of heat.

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