What amount of heat will be released during crystallization and subsequent cooling of 100 kg
| May 1, 2021 | education
What amount of heat will be released during crystallization and subsequent cooling of 100 kg of steel, if the initial steel temperature is 1400 ° C and the final temperature is 0 ° C?
The amount of heat released during cooling of the steel:
Q = Q1 + Q2.
Q1 = λ * m, where λ is the specific heat of melting of steel (λ = 0.84 * 10 ^ 5 J / (kg * K)), m is the mass (m = 100 kg).
Q2 = С * m * (tн – tк), where С – specific heat capacity of steel (С = 500 J / (kg * K)), tн – initial temperature (tн = 1400 ºС), tк – final temperature (tк = 0 ºС).
Q = Q1 + Q2 = λ * m + C * m * (tн – tк) = 0.84 * 10 ^ 5 * 100 + 500 * 100 * (1400 – 0) = 0.84 * 10 ^ 7 + 7 * 10 ^ 7 = 7.84 * 10 ^ 7 = 78.4 MJ.
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