What amount of heat will be released during the condensation of 200 g of water vapor at a temperature

What amount of heat will be released during the condensation of 200 g of water vapor at a temperature of 100 degrees, and cooling the resulting water to a temperature of 40 degrees?

The amount of heat released during condensation of water vapor and cooling of the resulting water is calculated by the formula: Q = Q1 + Q2 = L * m + C * m * (t1 – t2) = (L + C * (t1 – t2)) * m, where L is the specific heat of condensation of water vapor (23 * 10 ^ 5 J / kg); C – specific heat capacity of water (4200 J / (kg * K)); t1 – temperature of the beginning of condensation (100 ºС); t2 (final cooling temperature) = 40 ° C.

Calculation: Q = (23 * 10 ^ 5 + 4200 * (100 – 40)) * 0.2 = 510 400 J.

Answer: Heat will be released 510 400 J.