What amount of heat will be released during the condensation of 200 g

What amount of heat will be released during the condensation of 200 g of water vapor at a temperature of 100C and cooling the resulting water to a temperature of 40C?

Initial data: m (mass of water vapor) = 200 g = 0.2 kg; tк (final temperature of water cooling) = 40 ºС.

Reference data: t (temperature of boiling, condensation of water) = 100 ºС; L (specific heat of vaporization of water) = 23 * 10 ^ 5 J / kg; C (specific heat of water) = 4200 J / (kg * K).

The amount of heat that will be released during condensation of water vapor and subsequent cooling of water: Q = L * m + C * m * (t – tк) = 23 * 10 ^ 5 * 0.2 + 4200 * 0.2 * (100 – 40 ) = 510400 J = 510.4 kJ.