What amount of heat will be released during the crystallization of 5 kg of tin and with its further cooling to a temperature

What amount of heat will be released during the crystallization of 5 kg of tin and with its further cooling to a temperature of 32 degrees Celsius.

Given:
T1 = Tcr = 232 ° С
T2 = 32 ° C
l = 5.9 * 10 ^ 4 J / kg // (lambda) -specific heat of crystallization of tin
c = 230 J / (kg * ° C) // specific heat of tin
m = 5 kg
Decision:
1) Crystallization process
Q1 = l * m = 5.9 * 10 ^ 4 * 5 = 29.5 * 10 ^ 4 J
2) Cooling process
Q2 = cm (T1 – T2) = 230 * 5 * (232-32) = 23 * 10 ^ 4 J
3) The total amount of heat released:
Q = Q1 + Q2 = 23 * 10 ^ 4 + 29.5 * 10 ^ 4 = 52.5 * 10 ^ 4 J
Answer: 52.5 * 10 ^ 4 J