What amount of heat will be released during the crystallization of water weighing 1 kg

What amount of heat will be released during the crystallization of water weighing 1 kg taken at a temperature of 10 degrees Celsius?

Task data: m (mass of taken water) = 1 kg; t (initial water temperature) = 10 ºС.

Constants: C (specific heat capacity of water) = 4200 J / (kg * K); tcr (temperature at which water crystallization will begin) = 0 ºС; λ (specific heat of crystallization of water) = 3.4 * 10 ^ 5 J / kg.

The released amount of heat can be determined by the formula: Q = Q1 (cooling) + Q2 (crystallization) = C * m * (t – tcr) + λ * m = m * (C * (t – tcr) + λ).

Calculation: Q = 1 * (4200 * (10 – 0) + 3.4 * 10 ^ 5) = 382,000 J (382 kJ).