What amount of heat will be released during the solidification of 2 tons of molten aluminum taken

What amount of heat will be released during the solidification of 2 tons of molten aluminum taken at the melting temperature and cooled to a temperature of 60 degrees?

m = 2 t = 2000 kg
t1 = 660 C – melting point of aluminum
t2 = 60 C
L = 3.9 * 10 ^ 5 J / kg – specific heat of fusion of aluminum
С = 920 J / kg * С – specific heat of aluminum
Q -?
Q1 = L * m – the formula for the amount of heat required for solidification of aluminum
Q2 = C * m * (t2-t1) – the formula for the amount of heat required to cool aluminum to 60 C
Q = Q1 + Q2
Q1 = 2000 * 3.9 * 10 ^ 5 = 780 * 10 ^ 6 J = 780 MJ
Q2 = 920 * 2000 * (660-60) = 1104 * 10 ^ 6 J = 1104 MJ
Q = 780 + 1104 = 1884 MJ