What amount of heat will be released in 10 minutes in a 1 kΩ resistor if it is included in a 100 V voltage circuit?
| September 6, 2021 | education
t = 10 min = 600 s.
R = 1kΩ = 1000Ω.
U = 100 V.
Q -?
In the resistor to which the voltage U is applied, during the time t, the amount of thermal energy is released, the value of which is expressed by the Joule-Lenz law: Q = U ^ 2 * t / R, where R is the resistance of the resistor.
The time t = 10 minutes will be converted into the units of the international system C, that is, in seconds.
t = 10 min = 10 * 60 s = 600 s.
Q = (100 V) ^ 2 * 600 s / 1000 Ohm = 6000 J.
Answer: Q = 6000 J of thermal energy will be released in the resistor.
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