What amount of heat will be released in 30 minutes by a wire spiral with a resistance of 20 ohms at a current of 5 A.

t = 30 min = 1800 s.
R = 20 ohms.
I = 5 A.
Q -?
According to the Joule-Lenz law, the amount of heat in a conductor through which an electric current flows is determined by the formula: Q = I ^ 2 * R * t.
Where I is the current in the conductor, R is the resistance of the conductor, t is the time the current passes through the conductor.
Q = (5 A) ^ 2 * 20 Ohm * 1800 s = 900000 J.
Answer: heat released in the wire spiral Q = 900000 J.