What amount of heat will be released in a 50 Ohm rheostat in 2 minutes with a current in the circuit of 2 A?

Initial data: R (rheostat resistance) = 50 Ohm; t (time of movement of electric current through the rheostat) = 2 min; I (current in the circuit) = 2 A.

SI system: t = 2 min = 2 * 60 s = 120 s.

The amount of heat that is released on the rheostat can be calculated using the Joule-Lenz law: Q = I ^ 2 * R * t.

Let’s calculate: Q = 2 ^ 2 * 50 * 120 = 24000 J or 24 kJ.

Answer: 24 kJ of heat will be released on the rheostat.



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