What amount of heat will be released Q will emit during t = 1 min a current I = 0.5A
| April 25, 2021 | education
What amount of heat will be released Q will emit during t = 1 min a current I = 0.5A, passing through a lamp with a resistance of R = 220 Ohm?
The amount of heat that is released on the lamp in 1 minute is calculated according to the Joule-Lenz law:
Q = I² * R * t, where I is the value of the current on the lamp (I = 0.5 A), R is the resistance of the lamp (R = 220 Ohm), t is the time of passage of electric current through the lamp (t = 1 min = 60 s).
Let’s calculate the amount of heat:
Q = I² * R * t = 0.52 * 220 * 60 = 3300 J = 3.3 kJ.
Answer: Within 1 minute, 3.3 kJ of heat will be released on the lamp.
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