What amount of heat will be released when converting 250 g of centigrade steam into water

What amount of heat will be released when converting 250 g of centigrade steam into water, the temperature of which is 20C?

Task data: m (mass of water (water vapor)) = 250 g (0.25 kg); t (temperature to which the formed water will cool down) = 20 ºС.

Reference values: tк (temperature of the beginning of water vapor condensation) = 100 ºС; L (specific heat of condensation of water vapor) = 23 * 10 ^ 5 J / kg; C (specific heat of water) = 4200 J / (kg * K).

Let’s compose a formula for calculating heat: Q = L * m + C * m * (tк – 0) = m * (L + C * (tк – t)).

Calculation: Q = 0.25 * (23 * 10 ^ 5 + 4200 * (100 – 20)) = 659,000 J (659 kJ).