What amount of heat will be released when turning into ice and further cooling the water taken at t = 20 ° C, mw = 200l

univerkov | November 18, 2020 | education

water cools down to 0 ° C.
Q1 = c1 * m * Δt = 4200 * 200 * 20 = 16.8 MJ.
heat release during crystallization:
Q2 = λ * m = 3.3 * 10⁵ * 200 = 66 MJ.
total amount of heat released:
Q = Q1 + Q2 = 16.8 +66 = 82.8 MJ.

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