What amount of heat will give off an iron part weighing 4.5 kg, cooled by 30 degrees?
| May 21, 2021 | education
Task data: m (weight of the iron part taken) = 4.5 kg; Δt (temperature change during cooling) = 30 ºС.
Reference values: Szh (specific heat of iron) = 460 J / (kg * K).
The heat given off by the iron part is determined by the formula: Q = Сж * m * Δt.
Calculation: Q = 460 * 4.5 * 30 = 62.1 * 10 ^ 3 J (62.1 kJ).
Answer: The taken iron part will give off 62.1 kJ of heat upon cooling.
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