What amount of heat will the conductor release R = 15 at I = 5A within an hour.
| December 1, 2020 | education
Q-?
R = 15Ω
I = 5A
t = 1 hour = 3600s
Let’s use the Joule-Lenz law:
Q = A = I ^ 2 * R * t
Q = 25A ^ 2 * 15Ω * 3600s = 1350000J = 1.35MJ)
Answer: 1.35MJ
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