What amount of hydrogen is released during the interaction of zinc with hydrochloric acid weighing 146 g?

The reaction of zinc with hydrochloric acid is described by the following chemical reaction equation.

Zn + 2HCl = ZnCl2 + H2;

When one mole of zinc dissolves, one mole of hydrogen is released. This requires two moles of hydrochloric acid.

Let’s find the amount of the substance contained in 146 grams of hydrochloric acid.

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 146 / 36.5 = 4 mol;

In the course of the reaction, half the amount of hydrogen will be released.

N H2 = N HCl / 2 = 4/2 = 2 mol;