What amount of hydrogen was obtained by the reaction of 23 g of sodium with water?
| May 10, 2021 | education
The equation for the reaction of sodium with water. During the reaction, alkali and free hydrogen are formed.
2Na + 2H2O = 2NaOH + H2.
Let’s calculate the number of moles of substances for sodium.
n (2Na) = 23 g / 23 g / mol = 1 mol.
There will be half the amount of hydrogen.
n (H2) = n (Na) / 2 = 1 mol / 2 = 0.5 mol.
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