What amount of iron substance reacted with dilution with sulfuric acid if 100.8 liters

What amount of iron substance reacted with dilution with sulfuric acid if 100.8 liters of hydrogen were released as a result of the reaction?

Given:
V (H2) = 100.8 L

To find:
n (Fe) -?

1) Fe + H2SO4 => FeSO4 + H2 ↑;
2) n (H2) = V / Vm = 100.8 / 22.4 = 4.5 mol;
3) n (Fe) = n (H2) = 4.5 mol.

Answer: The amount of Fe substance is 4.5 mol.



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