What amount of salt is formed by the interaction of 6.3 g of nitric acid with iron (III) hydroxide?

Let’s carry out the solution, write down the equation, select the coefficients:
3HNO3 + Fe (OH) 3 = Fe (NO3) 3 + 3H2O – ion exchange reaction, iron nitrate salt and water are formed;
Let’s calculate the molar mass:
M (HNO3) = 63 g / mol.
The number of moles of nitric acid is determined by the formula:
Y (HNO3) = m / M = 6.3 / 63 = 0.1 mol.
Let’s make the proportion:
0.1 mol (HNO3) – X mol Fe (NO3) 3;
-3 mol – 1 mol from here, X mol Fe (NO3) 3 = 0.1 * 1/3 = 0.03 mol.
Answer: The amount of iron nitrate salt is 0.03 mol.