What amount of salt was obtained by the interaction of 6.5 grams of zinc with hydrochloric acid?

univerkov | December 8, 2020 | education

Zn + 2HCL = Zncl2 + H2
n (Zn) = 6.5 / 65 = 0.1 mol
according to the reaction equation
n (H2) = n (Zn) = 0.1 mol
V (H2) = 0.1 * 22.4 = 2.24
We get the answer: 0.1 mol, 2.24

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