What amount of sodium chloride substance should be taken so that the solution contains the same number of chlorine

What amount of sodium chloride substance should be taken so that the solution contains the same number of chlorine ions as they are formed when 2 mol of aluminum chloride is dissolved?

Dissolution of aluminum chloride:
Al (Cl) 3 = Al (3 +) + 3Cl (1-).
It can be seen from the reaction that when 1 mol of aluminum chloride is dissolved, 3 mol of chlorine ions are obtained.
Dissolving sodium chloride:
NaCL = Na (+) + Cl (-).
When 1 mol of sodium chloride is dissolved, 1 mol of chlorine ions is formed.
Proportion:
1 mol Al (Cl) 3 -> 3 mol Cl (1-);
2 mol Al (Cl) 3 -> x mol Cl (1-);
x = 6.
Answer: 6 mol.