What amount of sodium hydroxide substance is required for the reaction with phosphorus oxide (5)

What amount of sodium hydroxide substance is required for the reaction with phosphorus oxide (5) to obtain 0.2 mol of sodium phosphate Na3Po4?

According to the condition of the problem, we compose the reaction equation:
6NaOH + P2O5 = 2Na3PO4 + 3H2O – ion exchange reaction, sodium phosphate was obtained;
M (NaOH) = 39.9 g / mol;
Let’s make a proportion according to the equation:
0.2 mol (Na3PO4) – X mol (NaOH);
-2 mol – 6 mol hence, X mol (NaOH) = 0.2 * 6/2 = 0.6 mol;
We find the mass of sodium hydroxide by the formula:
m (NaOH) = Y * M = 0.6 * 39.9 = 23.94 g.
Answer: to carry out the reaction, sodium hydroxide weighing 23.94 g is required.