What amount of substance and mass of sodium hydroxide is obtained by the interaction of 7 grams of sodium with water?

given:
m (Na) = 7 g
to find:
n (NaOH)
m (NaOH)
decision:
2Na + 2H2O = 2NaOH + H2
n (Na) = m: M = 7 g: 23 g / mol = 0.3 mol
n (Na): n (NaOH) = 2: 2 = 0.3 mol
m (NaOH) = n * M = 0.3 mol * 40 g / mol = 12 g
answer: 0.3 mol; 12 g



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