What amount of substance is 38 g of iron oxide (lll)?
| January 17, 2021 | education
Given:
m (Fe2O3) = 38 g
Find: n (Fe2O3)
Decision:
n (Fe2O3) = m / M = 38 g / 160 g / mol = 0.238 mol
Answer: the amount of iron oxide substance (lll) is 0.238 mol.
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