What amount of substance is 88 g of copper (II) oxide?

univerkov | November 19, 2020 | education

Given:
m (CuO) = 88 g
To find
n (CuO) -?
Decision:
M (CuO) = 64 + 16 = 80 g / mol
n (CuO) = m (CuO) / M (CuO) = 88 g / 80 g / mol = 1.1 mol
Answer: 1.1 mol

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