What amount of substance (mol) is 460 g of magnesium bromide MgBr2?

univerkov | December 21, 2020 | education

we first find the molar mass of magnesium bromide M (MgBr2) = 24 + 2 * 80 = 184 g / mol
then we look for the amount of substance by the formula n = m / M
where m is the mass, which, according to the problem statement, is equal to 460
looking for n (MgBr2) = 460 g / 184 g / mol = 2.5 mol
the answer is 2.5 mol

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