What amount of video memory in MB is required to store two pages of an image, provided that the resolution

What amount of video memory in MB is required to store two pages of an image, provided that the resolution of the monitor is 604 * 480 pixels and the color depth is 32?

If the resolution of the monitor is 604 * 480, then the screen contains 289920 pixels.

To store the possible 32 colors, 5 bits of memory are required (2 ^ 5 = 32).

Therefore, it will take 289920 * 5 = 1449600 bits to store one screen page.

To store two pages of the screen, you will need 2 times more memory: 1449600 * 2 = 2899200 bits.

1 byte = 8 bits, therefore 2899200 bits = 362400 bytes.

1 KB = 1024 bytes, therefore 362400 bytes = 353.90625 KB

1 MB = 1024 KB, therefore 353.90625 KB = about 0.35 MB.

Answer: 0.35 MB.