What are the period and frequency of rotation of the wheel if the wheel has made 60 revolutions in a time equal to 2 minutes?

Given:

t = 2 minutes = 120 seconds – time span;

n = 60 revolutions – the number of wheel revolutions during the time interval t.

It is required to determine the wheel speed u (Hertz) and its rotation period T (seconds).

Find the wheel speed:

u = n / t = 60/120 = 0.5 Hertz.

Then the period of rotation of the wheel will be equal to:

T = 1 / u = 1 / 0.5 = 2 seconds.

Answer: the wheel rotation speed is 0.5 Hertz, the wheel rotation period is 2 seconds.