What are the points A (1; 3); B (0; 5); C (-1; -3); Р (2; 3) belong to the graph of the function y = 5-2x ^ 2.

y = 5 – 2x ^ 2. To find out if a point belongs to the graph, you need to substitute its coordinates into the equation of the function and check whether the equality is observed.

1) A (1; 3), coordinate x = 1, coordinate y = 3. Substitute y = 5 – 2x ^ 2 into the equation.

3 = 5 – 2 * 1 ^ 2;

3 = 5 – 2;

3 = 3 (correct). Point A belongs to the graph of the function.

2) B (0; 5), coordinate x = 0, coordinate y = 5. Substitute y = 5 – 2x ^ 2 into the equation.

5 = 5 – 2 * 0 ^ 2;

5 = 5 – 0;

5 = 5 (correct). Point B belongs to the graph of the function.

3) С (-1; -3), x-coordinate = -1, y-coordinate = -3. Substitute y = 5 – 2x ^ 2 into the equation.

-3 = 5 – 2 * (-1) ^ 2;

-3 = 5 – 2;

-3 = 3 (wrong). Point C does not belong to the graph of the function.

4) Р (2; 3), coordinate x = 2, coordinate y = 3. Substitute in the equation y = 5 – 2x ^ 2.

3 = 5 – 2 * 2 ^ 2;

3 = 5 – 8;

3 = -3 (wrong). Point P does not belong to the graph of the function.