What are the probable genotypes and phenotypes of children from a marriage of a color blind

What are the probable genotypes and phenotypes of children from a marriage of a color blind woman to a visually healthy man?

Let’s designate the chromosome containing the gene for color blindness as Xd, then the chromosome with the gene that determines the well-being in relation to this disease will be XD.

A man who has normal color discrimination will be recorded as XD Y. He is capable of producing two types of sperm – XD and Y. They pass on a chromosome containing a healthy gene – XD to their daughters, and a color-blind Y chromosome to their sons.

A woman with color blindness has a genotype homozygous for the pathological gene – XdXd. They produce the same type of eggs Xd.

The offspring possible for a given married couple will be represented by the following two options:

heterozygote girls capable of normal color discrimination (XDXd) – 50%;

boys with color blindness (Xd Y) – 50%.