What are the sides of a right-angled triangle if its area is 12 cm2?

The area of ​​a right-angled triangle S is determined by the formula S = (1/2) * a * b, where a, b are the legs of a right-angled triangle. 12 = (1/2) * a * b, a * b = 24. So there may be such options:
1) a = 1, b = 24, the hypotenuse c according to the Pythogor theorem will be c = square root of (1 ^ 2 + 24 ^ 2) = square root of 577 = 24.02 cm. A = 1 cm, b = 24 cm, c = 24.02cm
2) a = 2, b = 12, the hypotenuse of c by Pythogor’s theorem will be c = square root of (2 ^ 2 + 12 ^ 2) = square root of 148 = 12.17 cm. A = 2 cm, b = 12 cm, s = 12.17cm
3) a = 3, b = 8, the hypotenuse c according to the Pythogor theorem will be c = square root of (3 ^ 2 + 8 ^ 2) = square root of 73 = 8.54 cm. A = 1cm, b = 24cm, c = 24.02cm
3) a = 4, b = 6, the hypotenuse of c by the Pythogor theorem will be c = square root of (4 ^ 2 + 6 ^ 2) = square root of 52 = 7.21 cm.a = 4 cm, b = 6 cm , s = 7.21cm



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