What buoyancy force will act on the human body during full immersion if the volume of the body is 150 dm3.

The buoyant force of Archimedes will act on the human body in water, which is equal to:
Fa = ρ * g * V, where ρ is the density of water (we take ρ = 1000 kg / m ^ 3), g is the acceleration of gravity (we take g = 9.8 m / s ^ 2), V is the volume of the submerged part of the body human (V = 150 dm ^ 3 = 0.15 m ^ 3).
Let’s calculate the buoyancy force of Archimedes:
Fa = ρ * g * V = 1000 * 9.8 * 0.15 = 1470 N = 1.47 kN.
Answer: The buoyancy force of Archimedes is 1.47 kN.