What charge passes through a nichrome wire 110 m long and a cross-sectional area of 1 mm2 in 1.5 min

What charge passes through a nichrome wire 110 m long and a cross-sectional area of 1 mm2 in 1.5 min if it is connected to a network with a voltage of 220 V. nichrome resistivity 1.1 ohm * mm2 / m

l = 110 m.

S = 1mm ^ 2.

t = 1.5 min = 90 s.

U = 220 V.

ρ = 1.1 Ohm * mm ^^ 2 / m.

q -?

The current in the conductor I is determined by the formula: I = q / t.

q = I * t.

Let us express the current strength I according to Ohm’s law for a section of the circuit: I = U / R.

The resistance of a cylindrical conductor R is expressed by the formula: R = ρ * l / S.

I = U * S / ρ * l.

q / t = U * S / ρ * l.

The formula for determining the charge that has passed through the conductor will be: q = U * S * t / ρ * l.

q = 220 V * 1 mm ^ 2 * 90 s / 1.1 Ohm * mm ^^ 2 / m * 110 m = 163.6 Cl.

Answer: a charge passed through the conductor q = 163.6 C.